Program in C++ to print digit pattern according to input number from user

(1.)  For printing this type structure in C++:

1

1 2

1 2 3 

1 2 3 4

1 2 3 4 5

Here as we seen the figure is in row and column form thus we have to declare two variable ( i and j ) for row and column respectively. Here we use for loop statement of c++.

/* program to print structure */
#include<iostream.h>

#include<conio.h>
void main()
{
int i,j,n ;
clrscr () ;
cout<<"\n Enter number of rows:" ;
cin>>n;
for (i=1;i<=n;i++)

{
    for (j=1;j<=i;j++)
    {

    cout<<"J":

    }

cout<<"\n" ;
}
getch () ;
}

Output screen :: 

Enter number of rows :: 5

output :: 

1

1 2

1 2 3 

1 2 3 4

1 2 3 4 5

 (2.)   For printing this type structure in C++:

1

2 2

3 3 3 

4 4 4 4

5 5 5 5 5

Here as we seen the figure is in row and column form thus we have to declare two variable ( i and j ) for row and column respectively. Here we use for loop statement of c++.

/* program to print structure */

#include<iostream.h>
#include<conio.h>
void main()
{
int i,j,n ;
clrscr () ;
cout<<"\n Enter number of rows:" ;
cin>>n;
for (i=1;i<=n;i++)

{
    for (j=1;j<=i;j++)
    {

    cout<<"i";

    }

cout<<"\n";
}
getch () ;
}

Output screen :: 

Enter number of rows :: 5

output :: 

1

2 2

3 3 3 

4 4 4 4

5 5 5 5 5

 (3.)  For printing this type structure in C++:

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15

Here as we seen the figure is in row and column form thus we have to declare two variable ( i and j ) for row and column respectively. Here we use for loop statement of c++.

/* program to print structure */

#include<iostream.h>
#include<conio.h>
void main()
{
int i,j,n,number=0;
clrscr () ;
cout<<"\n Enter number of rows:" ;
cin>>n;
for (i=1;i<=n;i++)

{
    for (j=1;j<=i;j++)
    {

    number++;

    cout<<"number" ;

    }

cout<<"\n" ;
}
getch () ;
}

Output screen :: 

Enter number of rows :: 5

output :

1

2 3

4 5 6

7 8 9 10

11 12 13 14 15