ALGORITHM OF CALCULATION OF ADDITION , SUB , MULTI , DIV OF A AND B IN C

Program To Input Two Number From User And Calculate Add,Sum,Multi,and Div Of The Number According To The Choice

/*program of menu driven program*//
# include <stdio.h>
void main ()
{
int a,b,c,choice ;
clrscr () ;
printf ("/n enter the first number :") ;
scanf ("%d", & a) ;
printf ("/n enter second number :");
scanf ("%d", & b) ;
printf ("/n you can perform the following operation :") ;
printf ("/n 1.addition :") ;
printf ("/n 2.subtraction :") ;
printf ("/n 3. multiplication :") ;
printf ("/n 4. division :") ;
printf ("/n enter your choice :") ;
scanf ("%d", & choice) ;
switch (choice)
{
case 1 ;

c= a+b ;
printf ("/n sum = %d", c) ;
break ;
case 2 ;
c= a-b ;
printf ("/n sub = %d", c) ;
break ;
case 3 ;
c= a*b ;
printf ("/n multi = %d", c) ;
break ;
case 4 ;
c= a\b ;
printf ("/n div = %d". c) ;
break ;
default :
printf ("/n invalid number :") ;
}
getch () ;
}

Output :: enter the first number :

                number is : 45

                enter second number 

                 number is : 35

c = 45 + 35 = 80   ( if choice is 1 )

c = 45 - 35 = 10     ( if choice is 2 )

c = 45 * 35 = 1575  ( if choice is 3 )

c = 45 / 35 = 1.2      ( if choice is 4 )

ALGORITHM : CALCULATE ADDITION , SUB , MULTI , DIV OF A AND B

This is program of having calculation according to the choice of user.

STEP 1. START.

STEP 2. INPUT A AND B AND THEN CHOICE.

STEP 3. [ CALCULATE ADDITION , SUB , MULTI , DIV OF A AND B ]

              

              1. IF ENTER CHOICE IS 1.

               2. PRINT " C = A + B ".

               3. IF ENTER CHOICE IS 2.

               4. PRINT " C = A - B ".

               5. IF ENTER CHOICE IS 3.

               6. PRINT " C = A * B ".

               7. IF ENTER CHOICE IS 4.

               8. PRINT " C = A / B ".

OTHERWISE

9. PRINT " INVALID CHOICE".

        { STEP 3 LOOP 9 IS END }

STEP 4. STOP