C Program to check given number is Armstrong number or not

What are Armstrong number ?

An armstrong number is a number which is equal to the sum of digit rise to the power of total number of digit in the number.

Example :: 3 , 370 , 153

Program to check armstrong number ::

#include <stdio.h>

#include <math.h>

void main ()

{

int n , add = 0 , rem = 0 , temp , cube , pow ;

clrscr () ;

printf ('\n  Enter a number:") ;

scanf ("%d", &n) ;

temp = n ;

while ( n != 0 )

{

rem = n % 10 ;

cube = pow ( rem , 3 ) ;

add = add + cube ;

n = n / 10 ;

}

if ( add == temp )

printf ("\n Number is armstrong:") ;

else

printf ("\n Number is not armstrong:") ;

getch ()

}

OUTPUT :: (A)  Enter a number :-

                      Enter number is 153

                      Number is armstrong

                    (B) Enter a number :-

                        Enter number is 29

                       Number is not armstrong

C program of armstrong using concept of FUNCTION ::

When a program grow in size and complexity then we break that program into small module . These module are known as the function . Function increases the understandably of a program logic using function module independent logic can be defined .

Function provides the concept of modularity in a program which is best method to divide a complex program .  

#include <stdio.h>

int root ( int , int ) ;

void main ()

{

int n , add = 0 , temp , rem , word = 0 ;

clrscr () ;

printf ("\n Enter a number:") ;

scanf ("%d", &n) ;

temp = n ;

while ( temp != 0 )

{

word++ :

temp = temp / 10 ;

}

temp = n ;

while ( temp != 0 )

{

rem = temp % 10 ;

add = add + root ( remainder , digit ) ;

temp = temp / 10 ;

}

if ( n == add )

printf ("\n armstrong number:") ;

else

printf ("\n not armstrong number:") ;

}

int root ( int n , int r ) 

{

int c , p = 1 ;

for ( c = 1 : c <= r : c++ )

p = p * n ;

return p ; 

}

getch () ;

}